# Solution

Let the runs scored by Ashok, Brijesh, Chetan, Deodhar, and Evan be A, B, C, D and E respectively.

Brijesh has scored 68 runs less than Ashok. Therefore B = A - 68.

Chetan has scored 52 runs more than Brijesh. Therefore C = B + 52.

Evan has scored 16 runs more than Deodhar but 26 runs less than Chetan. Therefore, E = D + 16 and E = C - 26.

The total runs scored by Chetan and Evan was 126. Therefore E + C = 126.

Now, E = C - 26 and E + C = 126; therefore, C - 26 + C = 126. So, 2C = 152. Therefore, C = 76.

E = C - 26; so, E = 76 - 26. Therefore, E = 50.

E = D + 16; therefore, 50 = D + 16. So, D = 34.

C = B + 52; therefore, 76 = B + 52. So, B = 24.

B = A - 68; therefore, 24 = A - 68. So, A = 92.

Thus, the Jolly Cricket Club has scored 276 runs (Ashok: 92, Brijesh: 24, Chetan: 76, Deodhar: 34, and Evan: 50).

Did I get it right? Or, did I goof up like the scorer?

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