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Let the runs scored by Ashok, Brijesh, Chetan, Deodhar, and Evan be A, B, C, D and E respectively.
Brijesh has scored 68 runs less than Ashok. Therefore B = A - 68.
Chetan has scored 52 runs more than Brijesh. Therefore C = B + 52.
Evan has scored 16 runs more than Deodhar but 26 runs less than Chetan. Therefore, E = D + 16 and E = C - 26.
The total runs scored by Chetan and Evan was 126. Therefore E + C = 126.
Now, E = C - 26 and E + C = 126; therefore, C - 26 + C = 126. So, 2C = 152. Therefore, C = 76.
E = C - 26; so, E = 76 - 26. Therefore, E = 50.
E = D + 16; therefore, 50 = D + 16. So, D = 34.
C = B + 52; therefore, 76 = B + 52. So, B = 24.
B = A - 68; therefore, 24 = A - 68. So, A = 92.
Thus, the Jolly Cricket Club has scored 276 runs (Ashok: 92, Brijesh: 24, Chetan: 76, Deodhar: 34, and Evan: 50).
Did I get it right? Or, did I goof up like the scorer?
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- Union Public Service Commission - www.upsc.gov.in
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- Indian School of Mines, Dhanbad - www.ismdhanbad.ac.in
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- Indian Institute of Information Technology, Allahabad (Deemed University) - www.iiita.ac.in
- Central Marine Fisheries Research Institute, Kochi - www.cmfri.com
- Tata Institute of Social Sciences, Mumbai - www.tiss.edu